The domain of sin-1[log3(x/3)] is
The domain of sin-1[log3(x/3)] is
- [-9, -1]
- [-9, 1]
- [-1,9]
- [1, 9]
Answer
Domain of sin-1x is [-1,1]
Therefore, -1 ≤ log3(x/3) ≤ 1
3-1 ≤ x/3 ≤ 3
1 ≤ x ≤ 9
Therefore, the domain of sin-1[log3(x/3)] is [1,9]
The correct option is D.