If the angle between the line x = (y - 1)/2 = (z - 3)/λ and the plane
If the angle between the line x = (y - 1)/2 = (z - 3)/λ and the plane x + 2y + 3z = 4 is cos-1(5/14) then λ is equal to
- 3/2
- 2/5
- 2/3
- 5/3
Answer
(x - 0)/1 = (y - 1)/2 = (z - 3)/λ
x + 2y + 3z = 4
Angle between the line and plane is
cos(90 - θ) = (a1a2 + b1b2 + c1c2) / √(a12 + b12 + c12)√(a22 + b22 + c22)
sinθ = 1 + 4 +3λ / √14 x √(5 + λ2) = 5 + 3λ / √14 x √(5 + λ2)
But given that angle between line and plane is
θ = cos-1(5/√14) = sin-1(3/√14)
sinθ = 3/√14
3/√14 = 5 + 3λ / √14 x √(5 + λ2))
The correct option is C.