Let the line (x - 2)/3 = (y - 1)/-5 = (z - 2)/2 lie in the plane
Let the line (x - 2)/3 = (y - 1)/-5 = (z - 2)/2 lie in the plane x + 3y - αz + β = 0. Then (α, β) equals
- (-5, 5)
- (5, -15)
- (-6, 7)
- (6, -17)
Answer
2 + 3 × 1 – α (–2) + β = 0
2α + β = –5
3 – 15 – 2α = 0
2α = –12
The correct option is C.