Let k be an integer such that the triangle with vertices (k, –3k), (5, k) and (–k, 2) has area 28 sq. units. Then the orthocentre of this triangle is at the point

- 2, -1/2
- 1, 3/4
- 1, -3/4
- 2, 1/2

**Solution**

k = 2

Orthocentre is 2, 1/2

**The correct option is D.**