Three numbers are chosen at random without replacement from {1, 2, 3, ...... 8}. The probability that their minimum is 3, given that their maximum is 6, is

- 2/5
- 1/4
- 3/8
- 1/5

**Answer**

Let A be the event that maximum is 6.

B be event that minimum is 3

P(A) = ^{5}C_{2} / ^{8}C_{3} (the numbers < 6 are 5)

P(B) = ^{5}C_{2} / ^{8}C_{3} (the numbers > 3 are 5)

P(A ∩ B) = ^{2}C_{1} / ^{8}C_{3}

Required probability is = P(A ∩ B) / P(A)

**The correct option is D.**