One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals

- 1/7
- 1/14
- 5/14
- 1/50

**Answer**

A = Events that sum of the digits on selected ticket is 8

= {08, 17, 26, 35, 44}

⇒ n(A) = 5

B = Event that product of digits is zero

= {00, 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 20, 30, 40}

⇒ n(B) = 14

**The correct option is C.**