100 g of water is heated from 30°C to 50°C ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4184 J/Kg/K)

  1. 2.1 kJ
  2. 4.2 kJ
  3. 8.4 kJ
  4. 84 kJ

Answer

ΔQ = MSΔT = 100 x 10-3 x 4.184 x 20 = 8.4 X 103

ΔQ = 84 kJ, ΔW = 0

ΔQ = ΔV + ΔW

V = 8.4 kJ

The correct option is C.

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