A body is falling from a height h. After it has fallen a height h/2, it will possess

- only potential energy
- only kinetic energy
- half potential and half kinetic energy
- more kinetic and less potential energy

### Answer

When a body is at height h,

Total Energy = Kinetic Energy (KE) + Potential Energy (PE)

At h, KE = 0 and PE = mgh

At the height h/2,

PE = mgh/2

KE = ½mv^{2}

From the equation of motion,

v^{2} = u^{2} + 2as

v^{2} = 2gh/2

v = √(gh)

So, KE = mgh/2

Therefore, the body possesses half kinetic energy and half potential energy.

**The correct option is C.**