A and B walk from X to Y, a distance of 27 km at 5 kmph and 7 kmph respectively. B reaches Y and immediately turns back meeting A at Z. What is the distance from X to Z?
- 24 km
- 25 km
- 20 km
- 22.5 km
As B is walking fast, he reached point Y earlier. He turns back and meets A. Total distance traveled by A and B is different, but time is same.
Time = Distance/Speed
Let the distance from X to Z be a
Total distance traveled by A = a at speed of 5 km/hr
Total distance traveled by B = 27 + (27 - a) = (54 - a) at speed of 7 km/hr
Total time taken by A = a/5
Time taken by B = (54 - a)/7
Since, they have met at the same time, they would have traveled for the same time.
a/5 = (54 - a)/7
7a = 5*(54 - a) = 270 - 5a
a = 22.5 km
The correct option is D.