What is the length of the perpendicular drawn from the centre of circle of radius r on the chord of length √3r?

- r/4
- r/2
- √2r
- r

Perpendicular from centre bisects the chord. Use pythagoras theorem:

x^{2} = r^{2} - (√3r/2)^{2}

x^{2} = r^{2}/4

x = r/2

**The correct option is B.**

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