In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is
In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is
- 0
- –1
- +1
- +2
Answer
Let the oxidation number of Ni in K4[Ni(CN)4] = x
1 × 4 + x × (–1) × 4 = 0
4 + x – 4 = 0
x = 0
The correct option is A.