Which of the following facts about the complex [Cr(NH_{3})_{6}]Cl_{3} is wrong?

- The complex is paramagnetic.
- The complex gives white precipitate with silver nitrate solution.
- The complex is an outer orbital complex.
- The complex involves d
^{2}sp^{3}hybridisation and is octahedral in shape.

**Answer**

In case of d^{3} configuration, the number of unpaired electrons remains 3 whether the ligand is strong field or weak field.

The hybridisation scheme can be shown as:

Hence, the complex is inner orbital complex as it involves (n-1)d orbitals for hybridisation.

3.93 = √(n(n+2))

So, n =3 (here n is number of unpaired electrons)

**The correct option is C.**