If g(x) = 0∫x cos4t dt, then g(x + π) equals
If g(x) = 0∫x cos4t dt, then g(x + π) equals
- g(x) - g(π)
- g(x) / g(π)
- g(x) + g(π)
- g(x).g(π)
Answer
g′(x) = cos 4x
g(x) = sin4x/4 + k
g(x) = sin4x/4 [g(0) = 0]
The correct option is C.
If g(x) = 0∫x cos4t dt, then g(x + π) equals
Answer
g′(x) = cos 4x
g(x) = sin4x/4 + k
g(x) = sin4x/4 [g(0) = 0]
The correct option is C.