If the integral ∫ (5 tan x / tan x − 2)dx = x + a ln |sin x - 2 cos x| + k
If the integral ∫ (5 tan x / tan x − 2)dx = x + a ln |sin x - 2 cos x| + k, then a is equal to
- -1
- 2
- -2
- 1
Answer
∫ (5 tan x / tan x - 2)dx = ∫ (5 sin x / sin x - 2 cos x)dx
∫ [2(cos x + 2 sin x) + (sin x - 2 cos x)] / (sin x - 2 cos x)dx
2∫ [(cos x + 2 sin x) / (sin x - 2 cos x)]dx + ∫dx + k
= 2 log |sin x – 2 cos x| + x + k
∴ a = 2
The correct option is B.