If two different numbers are taken from the set {0, 1, 2, 3, ..., 10}; then the probability that their sum as well as absolute difference are both multiple of 4, is

- 6/55
- 12/55
- 14/45
- 7/55

**Solution**

Consider two sequences: 0, 4, 8 and 2, 6, 10

Take both numbers from either of these sequences.

Hence, probability = (^{3}C_{2} + ^{3}C_{2})/^{11}C_{2}

= 6/55

**The correct option is A.**