The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal half of the distance between its foci, is:

- 4/√3
- √3
- 4/3
- 2/√3

**Answer**

Length of conjugate axis = half the distance between foci

2b = ½(2ae)

b = ae/2

Length of latus rectum = 2b^{2}/a = 8

b^{2} = 4a

ae^{2} = 16

a = 12

**The correct option is D.**