The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle having area as 154 sq. units. Then the equation of the circle is

- x
^{2}+ y^{2}+ 2x + 2y = 47 - x
^{2}+ y^{2}+ 2x - 2y = 47 - x
^{2}+ y^{2}- 2x + 2y = 62 - x
^{2}+ y^{2}- 2x + 2y = 47

**Answer**

πr^{2} = 154

r = 7

For centre, on solving equation

2x - 3y = 5 & 3x - 4y = 7 or x = 1, y = 1 centre = (1, -1)

Equation of circle: (x - 1)^{2} + (y + 1)^{2} = 72

**The correct option is D.**