The eccentricity of the hyperbola whose length of the latus rectum is equal to 8

The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal half of the distance between its foci, is:

  1. 4/√3
  2. 2/√3
  3. √3
  4. 4/3

Solution

Length of conjugate axis = half the distance between foci

2b = ½(2ae)

b = ae/2

Length of latus rectum = 2b2/a = 8

b2 = 4a

a2e2/4 = 4a

ae2 = 16

a2(e2 - 1) = 4a

ae2 - a = 4

16 - a = 4

a = 12

ae2 = 16

e2 = 4/3

e = 2/√3

The correct option is B.