The eccentricity of the hyperbola whose length of the latus rectum is equal to 8
The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal half of the distance between its foci, is:
- 4/√3
- 2/√3
- √3
- 4/3
Solution
Length of conjugate axis = half the distance between foci
2b = ½(2ae)
b = ae/2
Length of latus rectum = 2b2/a = 8
b2 = 4a
a2e2/4 = 4a
ae2 = 16
a2(e2 - 1) = 4a
ae2 - a = 4
16 - a = 4
a = 12
ae2 = 16
e2 = 4/3
e = 2/√3
The correct option is B.