The locus of the foot of perpendicular drawn from the center of the ellipse x2 + 3y2 = 6 on any tangent to it is
Let the foot of perpendicular be P(h,k)
Equation of tangent with slope m passing P(h, k) is
y = mx ± √(6m2 + 2), where m = -h/k
√(6h2/k2 + 2) = (h2 + k2)/k
6h2 + 2k2 = (h2 + k2)2
The correct option is D.