The current voltage relation of diode is given by I = (e^{1000V/T} - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ± 0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?

- 0.02
- 0.2
- 0.05
- 0.5

**Answer**

Given is

5 = e^{1000V/T} - 1

This implies, 6 = e^{1000V/T}

Again, I = e^{1000V/T} - 1

dI/dV = e^{1000V/T} * 1000/T

dI = e^{1000V/T} * 1000/T dV

dI = 0.2 mA

**The correct option is B.**