The current voltage relation of diode is given by I = (e1000V/T - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ± 0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?

1. 0.02
2. 0.2
3. 0.05
4. 0.5

Given is

5 = e1000V/T - 1

This implies, 6 = e1000V/T

Again, I = e1000V/T - 1

dI/dV = e1000V/T * 1000/T

dI =  e1000V/T * 1000/T dV

dI = 0.2 mA

The correct option is B.