The current voltage relation of diode is given by
The current voltage relation of diode is given by I = (e1000V/T - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ± 0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?
- 0.02
- 0.2
- 0.05
- 0.5
Answer
Given is
5 = e1000V/T - 1
This implies, 6 = e1000V/T
Again, I = e1000V/T - 1
dI/dV = e1000V/T * 1000/T
dI = e1000V/T * 1000/T dV
dI = 0.2 mA
The correct option is B.