Find the 10th term of the AP: 2, 7, 12, ...

### Solution

a = 2

d = 7 – 2 = 5

n = 10

a_{n} = a + (n – 1)d

a_{10} = 2 + (10 – 1) × 5 = 2 + 45 = 47

Therefore, the 10^{th} term of the given AP is 47.

Find the 10th term of the AP: 2, 7, 12, ...

a = 2

d = 7 – 2 = 5

n = 10

a_{n} = a + (n – 1)d

a_{10} = 2 + (10 – 1) × 5 = 2 + 45 = 47

Therefore, the 10^{th} term of the given AP is 47.