If the sum of the first 14 terms of an AP is 1050 and its first term is 10
If the sum of the first 14 terms of an AP is 1050 and its first term is 10, find the 20th term.
Solution
Here,
S14 = 1050
n = 14,
a = 10
Sn = n/2 [2a + (n - 1)d]
1050 = 14/2 [20 + 13d]
1050 = 140 + 91d
910 = 91d
d = 10
Therefore,
a20 = 10 + (20 – 1) × 10 = 200
The 20th term is 200.