A circle of radius 10 cm has an equilateral triangle inscribed in it
A circle of radius 10 cm has an equilateral triangle inscribed in it. The length of the perpendicular drawn from the centre to any side of the triangle is
- 5√3 cm
- 5 cm
- 10√3 cm
- 10 cm
Answer
Let the length of perpendicular = OD.
In ΔBOD,
sin 30° = OD/OB
OD = 1/2 x 10 = 5
The correct option is B.
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