A circle of radius 10 cm has an equilateral triangle inscribed in it. The length of the perpendicular drawn from the centre to any side of the triangle is

- 5√3 cm
- 5 cm
- 10√3 cm
- 10 cm

Let the length of perpendicular = OD.

In ΔBOD,

sin 30° = OD/OB

OD = 1/2 x 10 = 5

**The correct option is B.**

- Let P, Q, R be the mid-points of sides AB, BC, CA respectively of a triangle ABC
- ABC is a triangle with AB = BC and D is an interior point
- AB, CD and EF are three parallel lines, in that order
- In the figure given, LM is parallel to QR
- PQRS is a parallelogram. PA bisects angle P and SA bisects angle S