A person travels a certain distance at 3 km/h and reaches 15 min late
A person travels a certain distance at 3 km/h and reaches 15 min late. If he travels at 4 km/h, he reaches 15 min earlier. The distance he has to travel is
- 4.5 km
- 6 km
- 7.2 km
- 12 km
Answer
Let the time taken to travel at speeds 3 km/h and 4 km/h be t1and t2 respectively.
So, t1 - t2 = 15 - (-15) = 30 minutes = 0.5 h
Now, let the distance travelled be = x km
So, (x / 3) - (x / 4) = 0.5
⇨ x = 6 km
The correct option is B.