In the figure given below, PQRS is a parallelogram. PA bisects angle P and SA bisects angle S. What is angle PAS equal to?
Since PQRS is a parallelogram,
∠P + ∠S = 180°
PA bisects ∠P and SA bisects ∠S,
∠PSA + ∠APS = 180°/2 = 90°
In the triangle PAS
∠PAS + ∠PSA + ∠APS = 180°
∠PAS = 180° - 180°/2 = 90°
The correct option is C.