Laws of Motion

A block of mass m is placed on a surface with a vertical cross section given by y = x3/6. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is:

  1. 1/6 m
  2. 1/3 m
  3. 1/2 m
  4. 2/3 m

Solution

mg sin θ = μ mg cosθ

tan θ = μ

dy/dx = tan θ = μ = 1/2

y = x3/6

dy/dx = x2/2 = 1/2

x = 1

y = 1/6 m

The correct option is A.