A spring balance is attached to the ceiling of a lift
A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/s2, the reading of the spring balance will be
- 15 N
- 24 N
- 49 N
- 74 N
Answer
When lift is stationary,
W1 = mg
When the lift descends with acceleration a,
W2 = m(g – a)
W2/W1 = (g – a)/g
= (9.8 - 5)/9.8 = 4.8/9.8
W2 = W1 x (4.8/9.8)
= 49 x (4.8/9.8)
= 24 N
The correct option is B.