When forces F1, F2, F3 are acting on a particle of mass m

• Laws of Motion

When forces F₁, F₂, F₃ are acting on a particle of mass m such that F₂ and F₃ are mutually perpendicular, then the particle remains stationary. If the force F₁ is now removed then the acceleration of the particle is

1. F₁/m
2. (F₂ - F₃)/m
3. (F₂F₃)/(mF₁)
4. F₂/m

Answer

The particle remains stationary on the application of three forces that means the resultant force is 0.

This implies

F₁ = - (F₂ + F₃)

Since, if the force F₁ is removed, the forces acting are F₂ and F₃, the resultant of which has the magnitude of F₁.

Therefore, the acceleration of the particle is F₁/m

The correct option is A.