A light string passing over a smooth light pulley connects two blocks of masses m_{1} and m_{2} (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

- 5:3
- 4:3
- 8:1
- 9:7

**Solution**

Since the string is inextensible, therefore both the masses will have same acceleration a. Also, the string is frictionless and massless therefore it will have same tension at both the ends.

Suppose m_{2} is greater then m_{1} which means m_{2} is coming down and m_{1} is going up.

Using Newton's Second Law of motion on the block of mass m_{1}

T - m_{1}g = m_{1}a

Again, applying the second law on the block of mass m_{2}

m_{2}g - T = m_{2}a

Given that a = g/8 or g = 8a

8m_{2}a - T = m_{2}a

T = 7m_{2}a

Substitute this value of T in the firs equation

7m_{2}a - 8m_{1}a = m_{1}a

7m_{2} = 9m_{1}

**The correct option is D.**